Answer:
The answer is "[tex]\frac{25}{3}[/tex]".
Step-by-step explanation:
please find the complete question in the attached file.
[tex]a_0=\frac{1}{10}\int^{5}_{x=-5} x^2 dx\\[/tex]
[tex]=\frac{1}{10} (\frac{x^3}{3})^{5}_{-5}\\\\=\frac{1}{30}[5^3+5^3]\\\\=\frac{2}{30}(125)\\\\=\frac{1}{15} \times 125\\\\=\frac{25}{3}[/tex]
