Step-by-step explanation:
Given that,
The length of a rectangle is (0.8x - 1.6) units
Width of a rectangle is (1/4x +1 ) units.
It is assumed to find the area of a rectangle.
AREA = l b, l is length and b is width
So,
[tex]A=(0.8x - 1.6)(\dfrac{x}{4}+1)\\\\A=0.8x\times \dfrac{x}{4}+0.8x-1.6\times \dfrac{x}{4}-1.6\\\\=0.2x^2+0.8x-0.4x-1.6\\\\=(0.2x^2+0.4x-1.6)\ \text{unit}^2[/tex]
Hence, this is the required solution.
