Respuesta :
Answer:
wavelength λ = 35.92 pm
Explanation:
Given that:
The glancing angle (θ) = 10.42°
Bragg reflection n = 1
wavelength λ = ???
diameter d = 99.3 pm
Using the formula:
nλ = 2dsinθ
we have:
1 × λ = 2 × ( 99.3) × sin (10.42°)
λ = 198.6 × 0.18086
λ = 35.92 pm
The wavelength of the X-rays that is used is equal to 35.9 nanometers.
Given the following data:
- Bragg reflection, n = 1
- Glancing angle (θ) = 10.42°.
- Distance between planes = 99.3 picometers.
To calculate the wavelength of the X-rays that is used, we would apply Bragg's law of reflection:
Mathematically, Bragg's law of reflection is given by the formula:
[tex]n\lambda = 2dsin\theta[/tex]
Where:
- n is Bragg reflection.
- d is the distance between crystal planes.
- [tex]\lambda[/tex] is the wavelength.
- [tex]\theta[/tex] is the reflection angle.
Substituting the given parameters into the formula, we have;
[tex]1 \times \lambda = 2 \times 99.3 \times 10^{-11} \times sin(10.42)\\\\ \lambda = 1.99 \times 10^{-9} \times 0.1809\\\\\lambda = 3.59 \times 10^{-10}[/tex]
Wavelength = 35.9 nanometers.
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