The length of FA is 5.33 units
The given parameters are:
[tex]\mathbf{EF = 8}[/tex]
[tex]\mathbf{ED = 10}[/tex]
[tex]\mathbf{EA = 13.33}[/tex]
EF and EA implies that point E is between line FA
So, the length of FA is calculated using:
[tex]\mathbf{FA = EA - EF}[/tex]
Substitute known values
[tex]\mathbf{FA = 13.33 - 8}[/tex]
Subtract
[tex]\mathbf{FA = 5.33}[/tex]
Hence, the length of FA is 5.33 units
Read more about lengths at:
https://brainly.com/question/18983323
