Solution :
From the output of regression equation given by
Number of death of children in 1991 = [tex]$-5.21226+1.003538 \times \text{ No. of child death in 1985}$[/tex]
Now, number of death of children in the year 1991 = [tex]$-5.21226+1.003538 \times \text{ No. of child death in 1985}$[/tex]
For x = no. of deaths of children in the year 1985 = 65
So substituting in the regression equation,
No. of deaths of children in year 1991 = [tex]$-5.21226+1.003538 \times 65$[/tex]
= [tex]$60.01771$[/tex]
≈ 60
Now residual = [tex]$\text{observed y - predicted y}$[/tex]
= [tex]$42-60$[/tex]
[tex]$-18$[/tex]
Part(a): Number of child deaths is,
[tex]1991=-5.21226+1.003538\times[/tex] number of child deaths in 1985
Part(b):
The number of child deaths in 1991 is 60.
Part(c): The observed is -18.
Part(a):
The given data can be solved by excel as,
From the output regression equation is,
Number of child deaths is,
[tex]1991=-5.21226+1.003538\times[/tex] number of child deaths in 1985
Part(b):
Number of child deaths is,
[tex]1991=-5.21226+1.003538\times[/tex] number of child deaths in 1985
For x=Number of child deaths in 1985=65
Number of child deaths in 1991 is,
[tex]-5.21226+1.003538\times65=60.01771\\=60[/tex]
Part(c):
Residual=observed y-predicted y
=42-60
=-18
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