Answer:
This question appear incomplete
Explanation:
This question appear incomplete because of the absence of the value of the count of the ions inside the unit cell. To determine the mass (in grams) of LiCl in a unit cell, the formula below can be used
count of ions inside the unit cell = mass of LiCl ÷ molar mass of LiCl
Hence,
Mass of LiCl = count of ions inside the unit cell × molar mass of LiCl
Count of ions (Li⁺ and Cl⁻ ions specifically) inside the unit cell should have been provided in the question
Molar mass of LiCl was given to be 42.39 g/mol
The mass of the LiCl unit cell has been 2.82 [tex]\rm \bold{\times\;e^-^2^2}[/tex] grams.
The given structure has been the unit cell of the LiCl having 4 atoms of Li and 4 atoms of Cl.
The number of Li and Cl in a molecule of LiCl has been 1, and 1 respectively.
The presence of 4 atoms of Li and Cl indicates that there has been the presence of 4 molecules of LiCl.
The molar mass ofLiCl = 42.39 g/mol.
The number of molecules present in a mole of the sample has been equivalent to the Avagadro number.
6.023 [tex]\rm \times\;10^2^3[/tex] molecules = 1 mole LiCl.
6.023 [tex]\rm \times\;10^2^3[/tex] molecules = 42.39 grams LiCl.
The mass of 4 molecules of LiCl has been:
4 molecules = [tex]\rm \dfrac{42.39}{6.023\;\times\;1^2^3}\;\times\;4[/tex]
4 molecules = 2.82 [tex]\rm \times\;10^-^2^2[/tex] grams
2.82 [tex]\rm \times\;10^-^2^2[/tex] grams = 2.82 [tex]\rm \bold{\times\;e^-^2^2}[/tex] grams.
The mass of the LiCl unit cell has been 2.82 [tex]\rm \bold{\times\;e^-^2^2}[/tex] grams.
For more information about the mass of a unit cell, refer to the link:
https://brainly.com/question/14020091
