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We have an aqueous solution that contains 35% (by mass) of a hypothetical solute Z. The formula weight of the solute Z is 118 g/mol. The density of the solution is observed to be 1.4 g/mL. What is the molarity of Z in this solution

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Answer:

4.15 M

Explanation:

In order to find the molarity of a stock solution of Z, we use the formula;

Co = 10pd/M

where;

p = percentage by mass of Z

d = density of Z

M= molar mass of Z

Substituting values;

Co= 10 * 35 * 1.4/118

C0= 4.15 M

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