A solenoid that is 133 cm long has a radius of 2.99 cm and a winding of 1740 turns; it carries a current of 3.91 A. Calculate the magnitude of the magnetic field inside the solenoid.

Respuesta :

Answer:

The value is  [tex]B = 0.0643 \ T[/tex]  

Explanation:

From the question we are told that

   The length of the solenoid is  [tex]L = 133 \ cm = 1.33 \ m[/tex]

     The radius is  [tex]r = 2.99 \ cm = 0.0299 \ m[/tex]

     The number of turns is [tex]N = 1740 \ turns[/tex]

     The current it carries is  [tex]I = 3.91 \ A[/tex]

Generally the magnitude of the magnetic field is mathematically represented as

           [tex]B = \frac{\mu_o * N * I}{L}[/tex]

Here  [tex]\mu_o[/tex]  is the permeability of free space with value  [tex]\mu_o = 4\pi *10^{-7} \ N/A^2[/tex]

=>      [tex]B = \frac{ 4\pi * 10^{-7} * 1740 * 3.91}{0.133}[/tex]  

=>      [tex]B = 0.0643 \ T[/tex]  

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