Answer:
1.60 [tex]ft^{2}[/tex]
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area = [tex]\pi[/tex][tex]r^{2}[/tex]
So that,
for the inner part of the pipe,
r = [tex]\frac{diameter}{2}[/tex]
= [tex]\frac{5}{2}[/tex]
= 2.5 feet
Area of the inner part of the pipe = [tex]\pi[/tex][tex]r^{2}[/tex]
= 3.14 x [tex](2.5)^{2}[/tex]
= 19.625
Are of the inner part of the pipe is 19.63 [tex]ft^{2}[/tex].
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r = [tex]\frac{5.2}{2}[/tex]
= 2.6 feet
Area of the pipe = [tex]\pi[/tex][tex]r^{2}[/tex]
= 3.14 x [tex](2.6)^{2}[/tex]
= 21.2264
Area of the pipe is 21.23 [tex]ft^{2}[/tex].
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60 [tex]ft^{2}[/tex].
