Answer:
[tex]0.833\ \text{m/s}^2[/tex]
Explanation:
m = Mass of block = 6 kg
F = Force on block = 5 N
[tex]\mu[/tex] = Coefficient of friction = 0
a = Acceleration of the block
From Newton's second law we have
[tex]F=ma\\\Rightarrow a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{5}{6}\\\Rightarrow a=0.833\ \text{m/s}^2[/tex]
The acceleration of the block is [tex]0.833\ \text{m/s}^2[/tex]
