Answer:
D = 3.81 x 10⁻² m = 3.81 cm
Explanation:
We can use the formula of fringe spacing from Young's Double Slit experiment to answer this question:
[tex]\Delta x = \frac{\lambda L}{d}\\[/tex]
where,
Δx = distance between two consecutive dark fringes
λ = wavelength of light beam = 5.37 x 10⁻⁷ m
L = Distance between screen and slits = 2.14 m
d = slit separation = 6.03 x 10⁻⁵ m
But, we need the distance between first dark fringe on 1 side to 2nd dark fringe on other side. It means we need twice the distance between two dark fringes:
[tex]D = 2\Delta x = 2\frac{\lambda L}{d}\\[/tex]
where,
D = distance between first dark fringe on one side and 2nd dark fringe on other side of central maximum = ?
Therefore,
[tex]D = \frac{(2)(5.37\ x\ 10^{-7} m)(2.14\ m)}{6.03\ x\ 10^{-5}\ m }[/tex]
D = 3.81 x 10⁻² m = 3.81 cm
