a rope is used to pull a 2.89kg bucket of water out of a deep well. what is the acceleration of the bucket when the tension in the rope is 30.2N?

Respuesta :

Answer:

Explanation:

Tension in the rope in upward direction = 30.2 N .

weight of bucket in downward direction = mg

net force in upward direction = 30.2 - mg

30.2 - 2.89 x 9.8

= 1.878 N

acceleration = net force / mass

= 1.878 / 2.89

= .65 m /s² .

= 65 cm /s²

The acceleration of the bucket will be "65 cm/s²".

Tension and acceleration:

Whenever the rope, thread, or cable is expanded underneath an applied force, a force is created in that as well, is a tension force.

Tension acts anywhere along the lengths of the string throughout the opposing directly proportional to the force acting upon that.

According to the question,

Tension in the rope = 30.2 N

Mass of bucket, m = 2.89 kg

Acceleration due to gravity, g = 9.8

Now,

The net force will be:

= Tension - mg

= [tex]30.2-(2.89\times 9.8)[/tex]

= [tex]1.878[/tex] N

hence,

The acceleration of the bucket be:

= [tex]\frac{Net \ force}{Mass}[/tex]

By substituting the values,

= [tex]\frac{1.878}{2.89}[/tex]

= [tex]0.65[/tex] m/s²

or,

= [tex]65[/tex] cm/s²

Thus the above approach is correct.

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