Respuesta :

maacastrobr

Answer:

Ksp = 2.58x10⁻⁹

Explanation:

The equilibrium that takes place is:

  • BaCO₃(s) ↔ Ba⁺² + CO₃⁻³
  • Ksp = [Ba⁺²] [CO₃⁻³]

The molar concentration of Ba⁺² at equilibrium is the solubility. The same can be said about CO₃⁻³:

  • Ksp = s * s
  • Ksp = s²

So now we can calculate the Ksp from the solubility, after converting the solubility from g/L to mol/L:

  • 0.0100 g BaCO₃/L ÷ 197.34 g/mol = 5.07x10⁻⁵ mol/L

Ksp = (5.07x10⁻⁵ mol/L)²

  • Ksp = 2.58x10⁻⁹

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