Answer:
All numbers less than 2 or [tex](-\infty, 1][/tex] or [tex](-\infty, 2)[/tex]
Step-by-step explanation:
Given that:
Number is added to itself is less than the number subtracted from 6.
To find:
All such numbers.
Solution:
Let the number be [tex]x[/tex].
Here, an inequality will be made.
When solved, it might give more than one answers.
As per the question statement, let us write the inequality.
Number added to itself [tex]\Rightarrow x +x =2x[/tex]
Number subtracted from six = [tex]6-x[/tex]
As per question:
[tex]2x<6-x\\\Rightarrow 3x<6\\\Rightarrow x<2[/tex]
So, the answer is:
All numbers less than 2 or [tex](-\infty, 1][/tex] or [tex](-\infty, 2)[/tex].
