Answer:
125ft³
Step-by-step explanation
Given the area of the sail boat expressed as [tex]A = 16\sqrt[3]{d^2}[/tex]. IF the area is 400ft², we are to find the displacement d;
Substitute A = 400 into the expression given and find d as shown;
[tex]A = 16\sqrt[3]{d^2}\\400 = 16\sqrt[3]{d^2}\\400/16 = \sqrt[3]{d^2}\\cube \ both \ sides\\(400/16)^3=( \sqrt[3]{d^2})^3\\64,000,000/4096 = d^2\\d = \sqrt{64,000,000/4096} \\d = 8,000/64\\d = 125 ft^3[/tex]
Hence the displacement of the hull of the sailboat is 125ft³