Answer:
[tex]V = 113.04m^3[/tex] --- Standard Model
[tex]Diameter = 15m[/tex] --- Larger Tank
Step-by-step explanation:
Given
Standard Model
[tex]Diameter = 6m[/tex]
Larger Tank
Diameter = 2.5 * Standard Model
Solving (a): Volume of Standard Model.
The tank is spherical; so, the volume (V) is as follows
[tex]V = \frac{4}{3}\pi r^3[/tex]
Where
[tex]r = \frac{1}{2}Diameter[/tex]
[tex]r = \frac{1}{2} * 6m[/tex]
[tex]r = 3m[/tex]
So:
[tex]V = \frac{4}{3}\pi r^3[/tex]
[tex]V = \frac{4}{3} * \pi * 3^3[/tex]
[tex]V = \frac{4}{3} * \pi * 27[/tex]
[tex]V = 4 * \pi * 9[/tex]
[tex]V = 4 * 9* \pi[/tex]
[tex]V = 36* \pi[/tex]
Take [tex]\pi[/tex] as 3.14
[tex]V = 36 * 3.14[/tex]
[tex]V = 113.04m^3[/tex]
Solving (b): Diameter of the larger tank
Diameter = 2.5 * Standard Model
[tex]Diameter = 2.5 * 6m[/tex]
[tex]Diameter = 15m[/tex]
Answer:
diameter =8.1
Step-by-step explanation:
The answer is from khan
