A cooling fan is turned off when it is running at 850 rev/min . It turns 1350 revolutions before it comes to a stop. What was the fan's angular acceleration, assumed constant

Respuesta :

Answer:

α = -0.47 rad/sec²

Explanation:

  • Assuming that the angular acceleration is constant, we can apply the following kinematic equation:

        [tex]\omega^{2}_{f} - \omega^{2}_o} = 2* \alpha* \Delta \theta (1)[/tex]

  • Since the fan comes to an stop, ωf = 0.
  • In order to get the value of the angular acceleration in rad/sec2, we neeed to convert first ω₀ to rad/sec, and Δθ, to rad, as follows:

       [tex]\omega_{o} = 850 rev/min * \frac{2*\pi rad}{rev} * \frac{1min}{60 sec} = 89 rad/sec (2)[/tex]

      [tex]\Delta \theta = 1350 rev *\frac{2*\pi rad}{1rev} = 8482.3 rad (3)[/tex]

  • Solving for α in (1):

       [tex]\alpha = \frac{-\omega_{o}^{2} }{2*\Delta\theta} = -0.47 rad/sec2 (4)[/tex]

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