Light of wavelength 510 nm is used to illuminate normally two glass plates 24.3 cm in length that touch at one end and are separated at the other by a wire of radius 0.023 mm. How many bright fringes appear along the total length of the plates.

Respuesta :

Answer:

[tex]m = 180 \ bright \ fringes[/tex]

Explanation:

From the question we are told that

    The  wavelength is  [tex]\lambda = 510 \ nm = 510 *10^{-9} \ m[/tex]

    The length of the of the plate is  [tex]l = 24.3 \ cm = 0.243 \ m[/tex]

    The radius of the wire  is [tex]r= 0.023 \ mm = 2.3 *10^{-5} \ m[/tex]

Generally the diameter of the wire which is the distance between the glass  plates is mathematically represented as

             [tex]d = 2 * r[/tex]

=>          [tex]d = 2 * 2.3 *10^{-5}[/tex]

=>          [tex]d = 4.6 *10^{-5} \ m[/tex]

 Generally the condition for constructive interference is mathematically represented as

           [tex]2 *d = m \lambda[/tex]

=>        [tex]m = \frac{2d}{\lambda}[/tex]

=>        [tex]m = \frac{2 * (4.6* 10^{-5})}{ 510 *10^{-9} }[/tex]

=>        [tex]m = 180 \ bright \ fringes[/tex]

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