Answer:
The acceleration is exactly 40 mi/h² as shown
Explanation:
Given;
initial velocity of the car, u = 30 mi/h
final velocity of the car, v = 50 mi/h
change in velocity, ΔV = v - u
ΔV = 50 mi/h - 30 mi/h = 20 mi/h
initial time, t₁ = 2:00 PM
final time, t₂ = 2:30 PM
Change in time, Δt = t₂ - t₁
Δt = 2: 30 - 2:00 = 30 mins = 0.5 hour
Acceleration is given as change in velocity per change in time;
a = ΔV / Δt
[tex]a = \frac{20 \ mi/h}{0.5 \ h}\\\\a = 40 \ mi/h^2 \ (shown)\\\\[/tex]
Therefore, the acceleration is exactly 40 mi/h² as shown.
