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A chemist has to prepare 750.0 mL of a 0.200 M KNO3(aq) solution. What mass, in grams, of potassium nitrate (formula mass 101.11 g/mol) would they use

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Answer:

They would use 15.17 g KNO₃.

Explanation:

To solve this problem first we calculate the number of KNO₃ moles that would be in the solution, multiplying the concentration times the volume:

  • moles = Concentration * Volume

750 mL ⇒ 750 / 1000 = 0.750 L

  • 0.200 M * 0.750 L = 0.150 mol KNO₃

Then we convert moles of KNO₃ to grams, using its molar mass:

  • 0.150 mol KNO₃ * 101.11 g/mol = 15.17 g KNO₃

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