Answer:
a. The cart's acceleration is 2 m/s^2
b. The cart will travel 100 m
c. The speed is 20 m/s
Explanation:
a. The acceleration of the cart can be calculated using Newton's second law:
F = m.a
Solving for a:
[tex]\displaystyle a=\frac{F}{m}[/tex]
The cart has a mass of m=15 Kg and is applied a net force of F=30 N, thus:
[tex]\displaystyle a=\frac{30}{15}[/tex]
[tex]a=2\ m/s^2[/tex]
b.
Now we use kinematics to find the distance and speed:
[tex]\displaystyle x = v_o.t+\frac{at^2}{2}[/tex]
The cart starts from rest (vo=0). The distance traveled in t=10 seconds is:
[tex]\displaystyle x = 0*10+\frac{2*10^2}{2}[/tex]
[tex]x = 100\ m[/tex]
The cart will travel 100 m
c.
The final speed is calculated by:
[tex]v_f=0+2*10=20\ m/s[/tex]
The speed is 20 m/s
