solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7

Question

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Respuesta :

absor201 absor201 · Answer 1 · 2020-12-04T12:58:42+01:00

Answer:

Solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 we get x=2 and y=-3

Solution set = {2,-3}

Step-by-step explanation:

We need to solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7

let:

[tex]3x-2y=12--eq(1)\\x+3y=-7 --eq(2)[/tex]

Finding value of x from equation 2 and putting in eq(1)

[tex]From \ eq(2)\\x+3y=-7\\x=-7-3y[/tex]

Putting value of x in eq(1)

[tex]3x-2y=12\\Put \ x=-7-3y\\3(-7-3y)-2y=12\\Solving\\-21-9y-2y=12\\-11y=12+21\\-11y=33\\y=\frac{33}{-11}\\y=-3[/tex]

So, we get y=-3

Now put value of y in equation 2 to find value of x

[tex]x+3y=-7\\x+3(-3)=-7\\x-9=-7\\x=-7+9\\x=2[/tex]

So, we get value of x =2

So, solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 we get x=2 and y=-3

Solution set = {2,-3}