Answer:
The slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2
Step-by-step explanation:
We know that the slope intercept-form of the line equation is
[tex]y=mx+b[/tex]
where m is the slope and b is the y-intercept
Given the equation
[tex]6x+3y=-63[/tex]
simplifying the equation to write in the slope-intercept form
[tex]y=-2x-21[/tex]
Thus, the slope = -2
As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so
The slope of the perpendicular line will be:
[tex]\frac{-1}{-2}=\frac{1}{2}[/tex]
Therefore, the slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2
