Answer:
solving the inequality we get [tex]\mathbf{x\geq 3}[/tex]
The graph is attached below.
Option C is correct option.
Step-by-step explanation:
We need to solve the inequality [tex]\frac{7x-3}{9}\geq 8-2x[/tex]
First we will solve the inequality to find value of x
Solving:
[tex]\frac{7x-3}{9}\geq 8-2x[/tex]
Step 1: Multiply both sides by 9
[tex]9(\frac{7x-3}{9})\geq 9(8-2x)\\7x-3\geq 72-18x[/tex]
Step 2: Adding 3 on both sides
[tex]7x-3+3\geq 72-18x+3\\7x\geq 75x-18x[/tex]
Step 3: Add 18x on both sides
[tex]7x+18x\geq 75-+18x\\25x\geq 75[/tex]
Step 4: Divide both sides by 25
[tex]\frac{25x}{25}\geq \frac{75}{25}\\x\geq 3[/tex]
So, solving the inequality we get [tex]\mathbf{x\geq 3}[/tex]
The graph is attached below.
Option C is correct option.
