Answer:
Option D
Step-by-step explanation:
[tex]F=\frac{9}{5}C+32\\\\F-32=\frac{9}{5}C \\\\5(F-32)=9C\\\\\frac{5(F-32)}{9}=C \\\\C=\frac{5}{9}( {F-32})[/tex]
For F=77°F
[tex]C=\frac{5}{9}(F-32) \\\\C=\frac{5}{9}(77-32)\\\\C=\frac{5}{9}(45)\\\\C=\frac{225}{9} \\\\C=25[/tex]
