A ball is thrown in the air at an angle of 60.0° to the ground, with an initial speed of 30m/s. How far from its original position does it land?

Respuesta :

Answer:

The distance is  [tex]R = 79.5 \ m[/tex]

Explanation:

From the question we are told that

     The angle at which the ball is thrown is [tex]\theta = 60^o[/tex]

     The initial speed is [tex]u = 30 \ m/s[/tex]

     

Generally the distance from the original position which the ball covered is mathematically  evaluated as

            [tex]R = \frac{ u^2 * sin 2\theta }{g}[/tex]

=>         [tex]R = \frac{ 30^2 * sin (2* 60)}{9.8}[/tex]  

=>         [tex]R = 79.5 \ m[/tex]

 

Q&A Education