Given:
Perimeter of a triangle = 17 inches
First side is twice the second.
Third side is 3 inches less than the second side.
To find:
The measure of the longest side.
Solution:
Let the second side be x. Then,
First side = 2x
Third side = x-3
We know that, perimeter of a triangle is the sum of all three sides of it.
[tex](2x)+x+(x-3)=17[/tex]
[tex]4x-3=17[/tex]
[tex]4x=17+3[/tex]
[tex]4x=20[/tex]
Divide both sides by 4.
[tex]x=5[/tex]
Now,
First side = [tex]2(5)=10[/tex] inches
Second side = 5 inches
Third side = [tex]5-3=2[/tex] inches
Therefore, the measure of the longest side is 10 inches.
