Answer:
Following are the solution to the given points:
Explanation:
In point a:
[tex]v_i = 4.56 \ \frac{m}{s}[/tex]
In point b:
The highest point : v=0
In point c:
[tex]a= -g \ \frac{m}{s^2} = -9.8 \frac{m}{s^2}[/tex]
In point d:
The highest point: [tex]a= -9.8 \ \frac{m}{s}[/tex]
In point e:
[tex]v^2=v_i^{2}+2g \Delta h \ \ \ \ \ \ Delta h=0\\\\v^2 = v_i^{2}\\\\v= 4.56 \ \ \frac{m}{s}[/tex]
Therefore, the velocity of the ball when it reaches into the hand [tex]4.56 \ \frac{m}{s}[/tex].
