Tracy deposited $59 into a bank account that earned 3.5% simple interest each year. If no money was deposited into or withdrawn from the account, how much money was in the account after ​ 1 1/2 ​ years? Round your answer to the nearest cent.

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ASIAX

Hi there!

The answer would be $62.10 because the formula for simple interest is I = P*r*t, so it's 59 * 0.035 * 1.5 = 62.10

Your friend, ASIAX

Answer:

Find out the how much money was in the account .

To prove

Formula

[tex]Simple\ interest = \frac{Principle\times Rate\times Time}{100}[/tex]

As given

Tracy deposited $59 into a bank account that earned 3.5% simple interest each year.

If no money was deposited into or withdrawn from the account .

Here

Principle = $59

Rate = 3.5%

[tex]Time = 1 \frac{1}{2}\ years[/tex]

[tex]Time = \frac{3}{2}\ years[/tex]

[tex]Time = 1.5\ years[/tex]

Put in the formula

[tex]Simple\ interest = \frac{59\times 3.5\times 1.5}{100}[/tex]

[tex]Simple\ interest = \frac{309.75}{100}[/tex]

Simple interest = $3.0975

Amount = Principle + Simple interest

             =  $59 + $ 3.0975

             = $ 62.0975

As 1 dollar = 100 cent

Now convert  $ 62.0975 in cent .

$ 62.0975 =  62.0975 × 100

                 = 6209.75 Cent

Therefore money was in the account  is 6209.75 Cent .



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