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A shipment of ball bearings with a mean diameter of 25 mm and a standard deviation of 0.2 mm is normally distributed. By how many standard deviations does a ball bearing with a diameter of 25.6 mm differ from the mean?

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The choices for this question can be found elsewhere and as follows:

0.6
1
2
3

We calculate as follows:

Mean = 25 mm
Standard Deviation = 0.2 mm
Value = 25.6 mm

25.6 - 25 = .6 mm
.6 mm / 0.2 mm = 3

Therefore, the correct answer is the last option, 3.

Answer:

3

Step-by-step explanation:

z represents the standard deviations:

z = (X - μ) / σ

z = (25.6 - 25) / 0.02

Once you calculate this, your answer will be three. I hope this helps!

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