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The angle between the hydrogen atoms in water (H2O) is slightly less than expected for a tetrahedral shape. This is because of the

Extra electron repulsion from the lone pairs.
Atomic radius of the oxygen atom.
Additional repulsion of the shared electrons.
Extra repulsion of the hydrogen atoms.

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I think the correct answer from the choices listed above would be the first option. The angle between the hydrogen atoms in water (H2O) is slightly less than expected for a tetrahedral shape. This is because of the extra electron repulsion from the lone pairs. Hope this helps.
shristiparmar1221

The angle between the hydrogen atoms in water (Hâ‚‚O) is slightly less than expected for a tetrahedral shape. This is because of the extra electron repulsion from the lone pairs. This follows VSEPR theory.

What is VSEPR theory ?

The valence shell electron pair repulsion (VSEPR) theory is a model used to predict 3-D molecular geometry based on the number of valence shell electron bond pairs among the atoms in a molecule or ion.

This model assumes that electron pairs will arrange themselves to minimize repulsion effects from one another.

According to VSEPR theory, the order of repulsion is lone pair - lone pair > lone pair - Bond pair > Bond pair - Bond pair

Hence, The angle between the hydrogen atoms in water (Hâ‚‚O) is slightly less than expected for a tetrahedral shape because of the extra electron repulsion from the lone pairs.

Learn more about VSEPR theory here ;

https://brainly.com/question/12775505

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