ball hit the ground is when the function equals zero
0=-16t^2+46t+6
we can't factor so use quadraticformula
for
ax^2+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]
x=[tex] \frac{-46+/- \sqrt{46^2-4(-16)(6)} }{2(-16)} [/tex]
x=[tex] \frac{-46+/- \sqrt{2116+384} }{-32} [/tex]
x=[tex] \frac{-46+/- \sqrt{2500} }{-32} [/tex]
x=[tex] \frac{-46+/- 50 }{-32} [/tex]
x=[tex] \frac{-46+ 50 }{-32} [/tex] or [tex] \frac{-46- 50 }{-32} [/tex]
x=[tex] \frac{4}{-32} [/tex] or x=[tex] \frac{-96}{-32} [/tex]
x=-1/6 or x=3
we cannot have negative time because time starts at 0
disregard -1/6 as a possible answer
answer is after 3 seconds
