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05-10-2016
Chemistry

contestada

how many moles of Fe2o3 are in 161 g of the compound ?

Respuesta :

05-10-2016

m = 161g
M = 56 * 2 + 16 * 3 = 160g/mol

n = m/M = 161g / 160g/mol = 1,00625 mol

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