The current in the lamp will be 0.66 ampere. It is found by multiplying the product of the resistance and square of the current. Its unit is the watt. It is the rate of the electric work done.
Electric power is the product of the resistance and square of the current. Its unit is the watt. It is the rate of the electric work done.
The given data in the problem is;
The resistance is,R=45 ohms
The power is represented as;P=80.0 watts
The electric current is,I
The formula for the electric power is given as;
[tex]\rm P= I^2R \\\\ \rm 20= I^2 \times 45 \\\\ I=0.66 \ ampere[/tex]
Hence, the current in the lamp will be 0.66 ampere.
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