The slope of the given line is required.
The slope is b. [tex]-\dfrac{3}{4}[/tex]
The given equation is
[tex]3x+4y=12[/tex]
This is in standard form.
Let us write it in slope intercept form which is done by isolating the value of y.
[tex]3x+4y=12\\\Rightarrow 4y=12-3x\\\Rightarrow y=\dfrac{12}{4}-\dfrac{3}{4}x\\\Rightarrow y=-\dfrac{3}{4}x+3[/tex]
The slope intercept form is given by
[tex]y=mx+c[/tex]
where [tex]m[/tex] is the slope and [tex]c[/tex] is the y intercept.
So, here the slope is b. [tex]-\dfrac{3}{4}[/tex]
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