Respuesta :
[H+] of basic solution = 10⁻¹¹·² = 6.31x10⁻¹² moldm³
[H+] of acidic solution = 10⁻²·⁴ = 3.98x10⁻³ moldm³
the diffrence is 3.9799x10⁻³ moldm³
hope that helps
[H+] of acidic solution = 10⁻²·⁴ = 3.98x10⁻³ moldm³
the diffrence is 3.9799x10⁻³ moldm³
hope that helps
Answer:
the difference in hydrogen ion concentration between these two solution is :[tex]3.9809\times 10^{-3} mol/L[/tex]
Explanation:
Concentration of hydrogen ions when pH of the solution is 11.2(alkaline)
[tex]pH=-\log[H^+][/tex]
[tex]11.2=-\log[H^+][/tex]
[tex][H^+]=6.3095\times 10^{-12} mol/L[/tex]
Concentration of hydrogen ions when pH of the solution is 2.4 (acidic).
[tex]pH=-\log[H^+]'[/tex]
[tex]2.4=-\log[H^+]'[/tex]
[tex][H^+]'=0.39810 mol/L[/tex]
In an acidic solution hydrogen ion s concentration always larger than that of of the alkaline solution.
[tex][H^+]'>[H^+][/tex]
The approximate difference in the concentration of hydrogen ions between the two solutions:
[tex][H^+]'-[H^+]=0.39810 mol/L-6.3095\times 10^{-12} mol/L=0.0039809 mol/L=3.9809\times 10^{-3} mol/L[/tex]