beshKimithluv
contestada

Consider this initial-rate data at a certain temperature for the reaction described by N2O3(
g. -> NO(
g. + NO2(
g. N2O3 (M) = .1 (initial rate= .66) = .2 (initial rate= 1.32) = .3 (initial rate= 1.98) find k ?

Respuesta :

taskmasters

N2O3(g)→NO(g)+NO2(g)

[N2O3] Initial Rate
0.1 M     r(t)=0.66 M/s
0.2 M     r(t)=1.32 M/s
0.3 M     r(t)=1.98 M/s

We can have the relationship:

([N2O3]/[N2O3]0)^m=r(t)/r0(t)
However,
([N2O3]/[N2O3]0) = 2

Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

r(t)/r0(t) = 2

r(t)=k[N2O3]

0.66 M/s=k×0.1 M

k=6.6 s−1

adefioyelaoye

The value of k is 6.6 s⁻¹ .

The reaction is given below:

N₂O₃(g)→NO(g)+NO₂(g)

[N₂O₃] Initial Rate Parameters

0.1 M     r(t)=0.66 M/s

0.2 M     r(t)=1.32 M/s

0.3 M     r(t)=1.98 M/s

We can have the relationship:

([N₂O₃]/[N₂O₃]0)^m= r(t)/r0(t)

Since we have ([N2O3]/[N2O3]0) = 2

We can deduce that

r(t)/r0(t) = 2

r(t)=k[N2O3]

0.66 M/s=k×0.1 M

k= 6.6 s⁻¹

Read more about Rate of reaction here https://brainly.in/question/1821142

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