Respuesta :
Answer: Correlation coefficient = 0.945 ( approx) and weight of a student increases as the height of the student increases.
Step-by-step explanation:
Here, value of x are 58, 59, 60, 62, 63, 64, 66, 68, 70
Value of y are, 122, 128, 126, 133, 145, 136, 144, 150, 151.
∑x = 570, ∑y= 1236, ∑ [tex]x^2[/tex]= 36234, ∑ [tex]y^2[/tex]= 170694
∑xy=78617
Thus the correlation coefficient,
[tex]r = \frac{n(\sum xy)- (\sum x)(\sum y)}{\sqrt{n\sum x^2 - (\sum x)^2} \sqrt{n\sum y^2-(\sum y)^2} }[/tex]
Where n is the number of the term.
here n = 9
thus, correlation coefficient
r = [tex]\frac{9\times 78617- 570\times 1236}{\sqrt{9\times 36234-(570)^2}\sqrt{9\times 170694-(1236)^2}}[/tex]
Thus, r= 0.94452987512
Which is closed to 0.95 and greater than 1
Therefore, weight of a student increases as the height of the student increases.
