Ans: 0.04 moles of N2 are essential to produce 0.08 moles of Li3N
Given :
Moles of Li3N generated = 0.08 moles
To determine:
Moles of N2 required
Explanation:
The chemical reaction is:
6Li + N2 → 2Li3N
Based on the reaction stoichiometry:
1 mole of N2 produces 2 moles of Li3N
Therefore, moles of N2 required to produce 0.08 moles of Li3N is:
[tex]= \frac{0.08 moles Li3N * 1 mole N2}{2 moles Li3N} \\\\= 0.04 moles N2[/tex]
