If a perimeter of a room is 78 feet, what is the area of the floor of the room?

There is a rectangular diagram with the longer written "2w+3"and shorter side has "w" written.

The equation to find the area of the rectangle is simply A = h * b. This means that the area of a rectangle is equal to the product of its height (h) by its base (b), or of its length by its width,on the other hand the perimeter of the rectangle is the total sum of all its sides P=2L+2W

Step

find the value of w

Let

L=2w+3

w=w

P=2L+2W

P=2(2w+3)+2w

P=4W+6+2W

P=6W+6

we know the perimeter is 78 feet

78=6w+6

isolating W

78-6=6W

72/6=W

W=12

step 2

find the area

A=l*w

let

l=2w+3

l=2(12)+3

length =27

w=w=12

width =12

A=l*w

A=27 feet * 12 feet

A=324 square feet

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If a perimeter of a room is 78 feet, what is the area of the floor of the room? There is a rectangular diagram with the longer written "2w+3"and shorter side has "w" written.

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If a perimeter of a room is 78 feet, what is the area of the floor of the room?

There is a rectangular diagram with the longer written "2w+3"and shorter side has "w" written.