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40.0 grams of liquid at its boiling point is
changed to vapor by the addition of 12800
joules of heat. What is the heat of
vaporization of the substance?

Respuesta :

quasarJose

Answer:

320J/g

Explanation:

Given parameters:

Mass of the liquid  = 40g

Amount of heat added  = 12800J

Unknown:

The heat of vaporization = ?

Solution:

The heat of vaporization can be related to heat added by the expression below;

           H  = mL

H is the heat added

m is the mass

L is the heat of vaporization

 Insert the parameters and solve;

          12800 = 40 x L

            L = [tex]\frac{12800}{40}[/tex]   = 320J/g

websitetechie

Question:

A student boils 9.43 grams of an unknown substance into vapor. If completely vaporizing the substance required 8,720 joules of energy, what is the heat of vaporization?

The heat of vaporization is ________ joules/gram.

Answer:

925

Explanation:

I got it correct in my test :)

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