Respuesta :
Answer:
2.4m
Explanation:
Given parameters:
Radius of circle = 1.65m
Acceleration = 3.5m/s²
Unknown:
Velocity of the object = ?
Solution:
To solve this problem, we have to apply the formula of centripetal acceleration;
Centripetal acceleration = [tex]\frac{v^{2} }{r}[/tex]
v is the velocity
r is the radius
v² = centripetal acceleration x radius
Insert parameters and solve;
v² = 3.5 x 1.65
v = √5.775 = 2.4m
The velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
Given the data in the question;
- Radius; [tex]r = 1.65m[/tex]
- Centripetal acceleration; [tex]a_c = 3.5m/s^2[/tex]
Velocity; [tex]v = \ ?[/tex]
From the centripetal force equation, we use the expression for centripetal acceleration:
[tex]a_c = \frac{v^2}{r}[/tex]
Where [tex]a_c[/tex] is the centripetal acceleration, v is the velocity and r is radius.
We substitute our given values into the equation
[tex]3.5m/s^2 = \frac{v^2}{1.65m} \\\\v^2 = 3.5m/s^2\ *\ 1.65m\\\\v^2 = 5.775m^2/s^2\\\\v = \sqrt{5.775m^2/s^2} \\\\v = 2.4m/s[/tex]
Therefore, the velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
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