Answer:
65,000
Explanation:
Black (B) is dominant to chestnut (b)
Trotting (T) is dominant to pacing (t)
A heterozygous black and h0m0zygous pacer (Bbtt) is crossed with a chestnut and heterozygous trotting (bbTt)
Bbtt x bbTt is the cross.
Potential alleles - Bt and bt bT and bt
Punnett square attached
Possible genotypes are: BbTt, bbTt
, Bbtt, bbtt
Black pacers have the genotype BBtt or Bbtt
1:4 of the offspring have The Bbtt genotype.
If there are 260,000 in the population, then 260,000 / 4 would be black pacers.
260,000/4 = 65,000
