What are the solutions to the quadratic equation 4(x + 2)2 = 36 x = −11 and x = 7 x = −7 and x = 11 x = −5 and x = 1 x = −1 and x = 5

Respuesta :

Answer:

c

Step-by-step explanation:

edge2020

The solutions to the quadratic equation 4(x + 2)² = 36 is x = -5 and x = 1.

Hence, option c) x = -5 and x = 1 is the correct answer.

What is a Quadratic Equation?

Quadratic equation is simply an algebraic expression of the second degree in x. Quadratic equation in its standard form is;

ax² + bx + c = 0

Where x is the unknown

To solve for x, we use the quadratic formula

x = (-b±√(b² - 4ac)) / (2a)

Given that;

4(x + 2)² = 36

4( x(x + 2) + 2(x+2) ) = 36

4( x² + 2x + 2x + 4 ) = 36

4( x² + 4x + 4 ) = 36

4x² + 16x + 16 = 36

4x² + 16x + 16 - 36 = 0

4x² + 16x - 20 = 0

We can further simply ( divide through by 4 )

x² + 4x - 5 = 0

Hence,

  • a = 1
  • b = 4
  • c = -5

x = (-b±√(b² - 4ac)) / (2a)

x = (-4±√(4² - (4 × 1 × -5)) / (2×1)

x = (-4±√(16 - (-20)) / (2)

x = (-4±√(16 + 20)) / (2)

x = (-4±√(36)) / 2

x = (-4±6)) / 2

Hence

x = (-4-6)) / 2 and x = (-4+6)) / 2

x = -10/2 and x = 2/2

x = -5 and x = 1

The solutions to the quadratic equation 4(x + 2)² = 36 is x = -5 and x = 1.

Hence, option c) x = -5 and x = 1 is the correct answer.

Learn more about quadratic equations here: brainly.com/question/1863222

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