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What is the molar mass of 18.12 g of gas
exerting a pressure of 3.05 atm on the
walls of a 5.85 L container at 280 K?

Respuesta :

Answer:

23.3 g/mol

Explanation:

The molar mass of 18.12 g of gas exerts a pressure of 3.05 atm on the walls of a 5.85 L container at 280 K is 23.3 g/mole.

What is the molar mass?

Molar mass is the concentration of a substance that is present in a specific liquid. It is also called the concentration of a substance.

The molar mass can be calculated by the formula of an ideal gas:

PV = nRT

P is the pressure

V is the volume

n is the number of moles

R is the constant of gas.

T is the temperature.

The given amounts are the molar mass of 18.12 g.

The pressure is 3.05 atm.

The volume is  5.85 L

The temperature is 280 K

Putting the value in the equation

n = PV/RT = (3.05) (5.85) / (0.0821) (280) = 0.777 moles of gas

Molar mass = 18.12 g/0.777 moles = 23.3 g/mole

Thus, the Molar mass is 23.3 g/mole.

To learn more about molar mass, refer to the below link:

https://brainly.com/question/22997914

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