I need help on these problems please be serious
Answer:
1. 10
2. 10
3. 12
4. [tex]3\sqrt{14}[/tex] or 11.22497216
Step-by-step explanation:
1. [tex]a^{2}+b^{2} =c^{2}\\\\a^{2} = 8^{2} = 64\\b^{2} = 6^{2} = 36\\c^{2} = a^{2} + b^{2} = 64 + 36 = 100\\c = \sqrt{100} = 10[/tex]
2. [tex]c^{2}-a^{2} =b^{2}\\\\a^{2} = 24^{2} = 576\\c^{2} = 26^{2} = 676\\b^{2} = c^{2} - a^{2} = 676 - 576 = 100\\b = \sqrt{100} = 10[/tex]
3.[tex]c^{2}-a^{2} =b^{2}\\\\a^{2} = 5^{2} = 25\\c^{2} = 13^{2} = 169\\b^{2} = c^{2} - a^{2} = 169 - 25 = 144\\b = \sqrt{144} = 12[/tex]
4. [tex]c^{2}-b^{2}=a^{2}\\\\b^{2} = 11^{2} = 121\\c^{2} = \sqrt{137}^{2} = 137\\a^{2} = c^{2} - b^{2} = 137 - 11 = 126\\a = \sqrt{126} = 3\sqrt{14} = 11.22497216[/tex]