A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s. it strikes a second hockey puck with a mass 0.11 kg. the first hockey puck comes to rest after the collision. What is the velocity of the second hockey puck after the collision? ( Round your answer to the nearest integer.)

Question

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MrRoyal MrRoyal · Answer 1 · 2020-11-14T02:51:34+01:00

Answer:

[tex]v_2 = 23.182m/s[/tex]

Explanation:

Given

[tex]m_1 = 0.17kg[/tex]

[tex]m_2 = 0.11kg[/tex]

[tex]u_1 = 15m/s[/tex] -- Initial Velocity of the first

[tex]u_2 = 0m/s[/tex] -- Initial Velocity of the second

[tex]v_1 = 0m/s[/tex] -- Final Velocity of the first

Required

Determine the final velocity of the second hockey puck ([tex]v_2[/tex])

This question illustrates law of conservation of momentum and it'll be solved using the following formula:

[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2[/tex] ---- law of conservation of momentum

Substitute in the right values

[tex]0.17 * 15 + 0.11*0 = 0.17 * 0 + 0.11*v_2[/tex]

[tex]0.17 * 15 + 0 = 0 + 0.11*v_2[/tex]

[tex]2.55 = 0.11*v_2[/tex]

Solve for v2

[tex]v_2 = 2.55/0.11[/tex]

[tex]v_2 = 23.182m/s[/tex]

Hence, the final velocity of the second hockey puck is 23.182m/s