Answer:
The answer is "[tex]247.19 \ \frac{MB}{sec}[/tex]".
Explanation:
over all pixels [tex]= 1,440 \times 900[/tex]
[tex]= 1,296,000\\\\= 1,296 \times 10^3[/tex]
[tex]time = 0.01 \ sec \\[/tex]
formula of time:
[tex]time= \frac{bits}{speed} \\\\speed= \frac{bits}{time}[/tex]
[tex]=\frac{1,296 \times 10^3 \times 16}{0.01}\\\\=20,736 \times 10^5 \ \frac{bytes}{second}\\\\=\frac{20,736 \times 10^5}{8} \ \frac{bytes}{second}\\\\= 2,592 \times 10^5 \ \frac{bytes}{second}\\\\= 247.19 \ \frac{MB}{sec}[/tex]
