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This diagram shows two different forces acting on a skateboarder. The
combined mass of the skateboard and the person is 72.3 kg. Based on this
information, what is the acceleration of the skateboarder?
Air resistance = 7.20 N
Applied force = 77.40 N
A. 0.97 m/s2 to the left
B. 0.97 m/s2 to the right
C. 3.21 m/s2 to the left
D. 3.21 m/s2 to the right

This diagram shows two different forces acting on a skateboarder The combined mass of the skateboard and the person is 723 kg Based on this information what is class=

Respuesta :

vanisher1122

Answer:

B

Explanation:

The acceleration of the skateboarder is 0.97m/s² to the right.

Given that the mass of the skateboard and the person is 72.3 kg.

Air resistance is 7.20N

Applied force is 77.40N

How acceleration of the skateboarder is calculated?

   According to Newton's Second law of motion, there will be the equal change in momentum per change in time.

Formula is F = ma

Here, we have to find acceleration, so that a = F ÷ m

Applied force - Air Resistance = 77.40 - 7.20 = 70.2.

Then, a = 70.2 ÷ 72.3

 

Thus, a = 0.97 m/s² to the right.

Learn more about Newton's Second Law

https://brainly.com/question/13447525

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