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(( E )) is the midpoint of BC ,

Thus ;

[tex]BE = CE = 6[/tex]

So :

[tex]BC = 12[/tex]

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[tex] \frac{AC}{2} = DE \\ [/tex]

[tex] \frac{AC}{2} = 7.5 \\ [/tex]

Multiply sides by 2

[tex]2 \times \frac{AC}{2} = 2 \times 7.5 \\ [/tex]

[tex]AC = 15[/tex]

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[tex] \frac{AB}{2} = EF \\ [/tex]

[tex] \frac{AB}{2} = 8 \\ [/tex]

Multiply sides by 2

[tex]2 \times \frac{AB}{2} = 2 \times 8 \\ [/tex]

[tex]AB = 16[/tex]

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[tex]∆ABC \: \: Perimeter =

AB + BC + AC \\ [/tex]

[tex]

∆ABC \: \: Perimeter = 16 + 12 + 15 \\ [/tex]

[tex]

∆ABC \: \: Perimeter = 43[/tex]

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Done...

The perimeter of triangle ABC is 43.

  • The calculation is as follows:

Since BE = CE = 6

So, BC = 12

Now

[tex]AC \div 2 = DE\\\\AC\div 2 = 7.5[/tex]

Now multiplied sides by 2

So,

[tex]2\times AC \div 2 = DE\\\\AC\div 2 = 7.5 \times 2[/tex]

AC = 15

Half of AB = EF

AB = 16

Now the perimeter is

= AB + BC + AC

= 16 + 12 + 15

= 43

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